Shanxian Chemical
SUPPLEMENTS
20 Pounds Aluminum Hydrogen Production
Twenty pounds of aluminum to produce hydrogen
Now there are twenty pounds of aluminum, and the amount of hydrogen produced is desired. It is a common law in chemistry that aluminum interacts with other substances to produce hydrogen.
The nature of aluminum is active, and it will react when it encounters suitable reagents. It is common for aluminum to meet acid, such as sulfuric acid and hydrochloric acid, which should be as follows: Aluminum ($Al $) reacts with hydrochloric acid ($HCl $) to form aluminum chloride ($AlCl_ {3} $) and hydrogen ($H_ {2} $). According to the chemical equation: $2Al + 6HCl = 2AlCl_ {3} + 3H_ {2}\ uparrow $.
From the formula, two moles of aluminum can produce three moles of hydrogen. First calculate the amount of twenty pounds of aluminum. One pound is about 453.592 dollars $g, and twenty pounds is 20 dollars\ times453.592 = 9071.84 $g. The molar mass of aluminum is about 27 dollars $g/mol, so the amount of twenty pounds of aluminum is $n (Al) =\ frac {9071.84g} {27g/mol}\ approx336.0mol $.
According to the above reaction ratio, let the amount of hydrogen produced is $n (H_ {2}) $, then $\ frac {n (Al) } {2} =\ frac {n (H_ {2}) } {3} $, that is, $n (H_ {2}) =\ frac {3} {2} n (Al) $. Substitute $n (Al) = 336.0mol $to get $n (H_ {2}) =\ frac {3} {2}\ times336.0mol = 504.0mol $.
The molar mass of hydrogen is 2 dollars $g/mol, so the mass of hydrogen produced is $m (H_ {2}) = n (H_ {2}) \ times M (H_ {2}) = 504.0mol\ times2g/mol = 1008 $g. If in liters, under standard conditions, the molar volume of the gas is about 22.4 dollars $l/mol, then the volume of hydrogen is $V (H_ {2}) = n (H_ {2}) \ times V_ {m} = 504.0mol\ times22.4L/mol = 11289.6 $L.
From this point of view, twenty pounds of aluminum can be reacted to obtain the amount of hydrogen as described above. This has important reference value in various fields such as chemical production and energy research.
Now there are twenty pounds of aluminum, and the amount of hydrogen produced is desired. It is a common law in chemistry that aluminum interacts with other substances to produce hydrogen.
The nature of aluminum is active, and it will react when it encounters suitable reagents. It is common for aluminum to meet acid, such as sulfuric acid and hydrochloric acid, which should be as follows: Aluminum ($Al $) reacts with hydrochloric acid ($HCl $) to form aluminum chloride ($AlCl_ {3} $) and hydrogen ($H_ {2} $). According to the chemical equation: $2Al + 6HCl = 2AlCl_ {3} + 3H_ {2}\ uparrow $.
From the formula, two moles of aluminum can produce three moles of hydrogen. First calculate the amount of twenty pounds of aluminum. One pound is about 453.592 dollars $g, and twenty pounds is 20 dollars\ times453.592 = 9071.84 $g. The molar mass of aluminum is about 27 dollars $g/mol, so the amount of twenty pounds of aluminum is $n (Al) =\ frac {9071.84g} {27g/mol}\ approx336.0mol $.
According to the above reaction ratio, let the amount of hydrogen produced is $n (H_ {2}) $, then $\ frac {n (Al) } {2} =\ frac {n (H_ {2}) } {3} $, that is, $n (H_ {2}) =\ frac {3} {2} n (Al) $. Substitute $n (Al) = 336.0mol $to get $n (H_ {2}) =\ frac {3} {2}\ times336.0mol = 504.0mol $.
The molar mass of hydrogen is 2 dollars $g/mol, so the mass of hydrogen produced is $m (H_ {2}) = n (H_ {2}) \ times M (H_ {2}) = 504.0mol\ times2g/mol = 1008 $g. If in liters, under standard conditions, the molar volume of the gas is about 22.4 dollars $l/mol, then the volume of hydrogen is $V (H_ {2}) = n (H_ {2}) \ times V_ {m} = 504.0mol\ times22.4L/mol = 11289.6 $L.
From this point of view, twenty pounds of aluminum can be reacted to obtain the amount of hydrogen as described above. This has important reference value in various fields such as chemical production and energy research.
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