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20 Volume Hydrogen Peroxide Percentage
When converting the concentration of hydrogen peroxide into
and the concentration of hydrogen peroxide, people often want to know the exact percentage of "20 volumes of hydrogen peroxide". This is related to many practical applications, including chemical and pharmaceutical products.
"20 volumes of hydrogen peroxide" means that every 1 volume of hydrogen peroxide decomposes under appropriate conditions to produce 20 volumes of oxygen. According to chemical principles, the equation for the decomposition of hydrogen peroxide is: $2H_ {2} O_ {2}\ longrightarrow 2H_ {2} O + O_ {2}\ uparrow $.
According to the knowledge of the molar volume of gas, under standard conditions, the volume occupied by 1 mole of any gas is about 22.4 liters. Let the amount of hydrogen peroxide in "20 volumes of hydrogen peroxide" be $x $mol. If 1 liter of this hydrogen peroxide decomposes to produce 20 liters of oxygen, the amount of oxygen is $n (O_ {2}) =\ frac {20L} {22.4L/mol} $. According to the stoichiometric ratio of the above equation, $n (H_ {2} O_ {2}) = 2n (O_ {2}) $, then $n (H_ {2} O_ {2}) = 2\ times\ frac {20L} {22.4L/mol} $.
The molar mass of hydrogen peroxide $M (H_ {2} O_ {2}) = 34g/mol $, so the mass of hydrogen peroxide in 1 liter of "20 volumes of hydrogen peroxide" $m (H_ {2} O_ {2}) = n (H_ {2} O_ {2}) \ times M (H_ {2} O_ {2}) = 2\ times\ frac {20L} {22.4L/mol}\ times34g/mol $.
It is also known that the mass of 1 liter of water is about 1000 grams. Let the mass fraction of hydrogen peroxide be $w $, then $w =\ frac {m (H_ {2} O_ {2}) } {m (H_ {2} O_ {2}) + m (H_ {2} O) }\ times100\% $, and $m (H_ {2} O_ {2}) = 2\ times\ frac {20L} {22.4L/mol}\ times34g/mol $and $m (H_ {2} O) = 1000g $Substitute to obtain:
$w =\ frac {2\ times\ frac {20} {22.4}\ times34} {2\ Times\ frac {20} {22.4}\ times34 + 1000}\ times100\% $. After calculation, the mass fraction of "20 volumes of hydrogen peroxide" is about 6%.
In summary, the percentage of "20 volumes of hydrogen peroxide" is about 6%. In practical applications, this number can provide an accurate basis for many operations, such as chemical preparation and medical disinfection.
and the concentration of hydrogen peroxide, people often want to know the exact percentage of "20 volumes of hydrogen peroxide". This is related to many practical applications, including chemical and pharmaceutical products.
"20 volumes of hydrogen peroxide" means that every 1 volume of hydrogen peroxide decomposes under appropriate conditions to produce 20 volumes of oxygen. According to chemical principles, the equation for the decomposition of hydrogen peroxide is: $2H_ {2} O_ {2}\ longrightarrow 2H_ {2} O + O_ {2}\ uparrow $.
According to the knowledge of the molar volume of gas, under standard conditions, the volume occupied by 1 mole of any gas is about 22.4 liters. Let the amount of hydrogen peroxide in "20 volumes of hydrogen peroxide" be $x $mol. If 1 liter of this hydrogen peroxide decomposes to produce 20 liters of oxygen, the amount of oxygen is $n (O_ {2}) =\ frac {20L} {22.4L/mol} $. According to the stoichiometric ratio of the above equation, $n (H_ {2} O_ {2}) = 2n (O_ {2}) $, then $n (H_ {2} O_ {2}) = 2\ times\ frac {20L} {22.4L/mol} $.
The molar mass of hydrogen peroxide $M (H_ {2} O_ {2}) = 34g/mol $, so the mass of hydrogen peroxide in 1 liter of "20 volumes of hydrogen peroxide" $m (H_ {2} O_ {2}) = n (H_ {2} O_ {2}) \ times M (H_ {2} O_ {2}) = 2\ times\ frac {20L} {22.4L/mol}\ times34g/mol $.
It is also known that the mass of 1 liter of water is about 1000 grams. Let the mass fraction of hydrogen peroxide be $w $, then $w =\ frac {m (H_ {2} O_ {2}) } {m (H_ {2} O_ {2}) + m (H_ {2} O) }\ times100\% $, and $m (H_ {2} O_ {2}) = 2\ times\ frac {20L} {22.4L/mol}\ times34g/mol $and $m (H_ {2} O) = 1000g $Substitute to obtain:
$w =\ frac {2\ times\ frac {20} {22.4}\ times34} {2\ Times\ frac {20} {22.4}\ times34 + 1000}\ times100\% $. After calculation, the mass fraction of "20 volumes of hydrogen peroxide" is about 6%.
In summary, the percentage of "20 volumes of hydrogen peroxide" is about 6%. In practical applications, this number can provide an accurate basis for many operations, such as chemical preparation and medical disinfection.
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