Shanxian Chemical
SUPPLEMENTS
Ammonia Oxygen Nitric Oxide Water Balanced
Ammonia-oxygen reaction produces a balance of nitric oxide and water
Now there is a combination of ammonia ($NH_3 $) and oxygen ($O_2 $) to form nitric oxide ($NO $) and water ($H_2O $). The chemical equation of this reaction is to find its balance.
Preliminary formula of the preceding reaction: $NH_3 + O_2\ longrightarrow NO + H_2O $
View hydrogen atoms, the number of hydrogen atoms in $NH_3 $is 3 dollars $, the number of hydrogen atoms in $H_2O $is 2 dollars $, and the least common multiple of 3 dollars $and 2 dollars $is 6 dollars $. Therefore, $NH_3 $is preceded by 2 dollars $, and $H_2O $is preceded by 3 dollars $. At this time, the formula becomes: $2NH_3 + O_2\ longrightarrow NO + 3H_2O $.
Looking at the nitrogen atom again, the number of nitrogen atoms in $2NH_3 $is 2 dollars $, so $NO $should be preceded by 2 dollars $, and the formula is: $2NH_3 + O_2\ longrightarrow 2NO + 3H_2O $.
Finally, look at the oxygen atoms, the number of oxygen atoms in $2NO $is 2 dollars $, the number of oxygen atoms in $3H_2O $is 3 dollars $, then the total number of oxygen atoms in the product is 2 dollars + 3 = 5 $, the number of oxygen atoms in $O_2 $is 2 dollars $, in order to make the number of oxygen atoms equal, $O_2 $should be preceded by $\ frac {5} {2} $, in this formula: $2NH_3 +\ frac {5} {2} O_2\ longrightarrow 2NO + 3H_2O $.
In order to make the coefficients integers, multiply both sides of the equation by 2 dollars $, and the equation is: $4NH_3 + 5O_2 = 4NO + 6H_2O $.
In summary, the chemical equation for the reaction of ammonia and oxygen to form nitric oxide and water is $4NH_3 + 5O_2 = 4NO + 6H_2O $.
Now there is a combination of ammonia ($NH_3 $) and oxygen ($O_2 $) to form nitric oxide ($NO $) and water ($H_2O $). The chemical equation of this reaction is to find its balance.
Preliminary formula of the preceding reaction: $NH_3 + O_2\ longrightarrow NO + H_2O $
View hydrogen atoms, the number of hydrogen atoms in $NH_3 $is 3 dollars $, the number of hydrogen atoms in $H_2O $is 2 dollars $, and the least common multiple of 3 dollars $and 2 dollars $is 6 dollars $. Therefore, $NH_3 $is preceded by 2 dollars $, and $H_2O $is preceded by 3 dollars $. At this time, the formula becomes: $2NH_3 + O_2\ longrightarrow NO + 3H_2O $.
Looking at the nitrogen atom again, the number of nitrogen atoms in $2NH_3 $is 2 dollars $, so $NO $should be preceded by 2 dollars $, and the formula is: $2NH_3 + O_2\ longrightarrow 2NO + 3H_2O $.
Finally, look at the oxygen atoms, the number of oxygen atoms in $2NO $is 2 dollars $, the number of oxygen atoms in $3H_2O $is 3 dollars $, then the total number of oxygen atoms in the product is 2 dollars + 3 = 5 $, the number of oxygen atoms in $O_2 $is 2 dollars $, in order to make the number of oxygen atoms equal, $O_2 $should be preceded by $\ frac {5} {2} $, in this formula: $2NH_3 +\ frac {5} {2} O_2\ longrightarrow 2NO + 3H_2O $.
In order to make the coefficients integers, multiply both sides of the equation by 2 dollars $, and the equation is: $4NH_3 + 5O_2 = 4NO + 6H_2O $.
In summary, the chemical equation for the reaction of ammonia and oxygen to form nitric oxide and water is $4NH_3 + 5O_2 = 4NO + 6H_2O $.
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