Shanxian Chemical
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How To Dilute 50 Hydrogen Peroxide To 3
On the method of dilution of hydrogen peroxide
Take 50% hydrogen peroxide and want to dilute it to a concentration of three. The theory should be explained in detail.
The reason for the dilution of the solution is that the amount of solute remains unchanged, while the amount of solvent increases. Let the amount of 50% hydrogen peroxide be\ (V_1\), and the amount of solute contained in it is\ (50\% V_1\). To obtain three% hydrogen peroxide, let the final solution volume be\ (V_2\). According to the reason that the solute remains unchanged, there is\ (50\% V_1 = 3\% V_2\).
From this, we can get\ (V_2 =\ frac {50\% V_1} {3\%} =\ frac {50} {3} V_1\). This means that when the volume of hydrogen peroxide taken is\ (V_1\), the volume of water to be added is\ (V_2 - V_1 =\ frac {50} {3} V_1 - V_1 =\ frac {47} {3} V_1\).
To dilute, when preparing a clean device, first measure a certain volume of\ (V_1\) of 50 hydrogen peroxide and pour it into it. Then take\ (\ frac {47} {3} V_1\) volume of purified water with a gauge, slowly inject it into the container containing hydrogen peroxide, stir when injecting, so that the two are fused seamlessly, so that you can get three of hydrogen peroxide. Between operations, be careful not to splash the solution, and pay attention to protection to ensure safety.
Take 50% hydrogen peroxide and want to dilute it to a concentration of three. The theory should be explained in detail.
The reason for the dilution of the solution is that the amount of solute remains unchanged, while the amount of solvent increases. Let the amount of 50% hydrogen peroxide be\ (V_1\), and the amount of solute contained in it is\ (50\% V_1\). To obtain three% hydrogen peroxide, let the final solution volume be\ (V_2\). According to the reason that the solute remains unchanged, there is\ (50\% V_1 = 3\% V_2\).
From this, we can get\ (V_2 =\ frac {50\% V_1} {3\%} =\ frac {50} {3} V_1\). This means that when the volume of hydrogen peroxide taken is\ (V_1\), the volume of water to be added is\ (V_2 - V_1 =\ frac {50} {3} V_1 - V_1 =\ frac {47} {3} V_1\).
To dilute, when preparing a clean device, first measure a certain volume of\ (V_1\) of 50 hydrogen peroxide and pour it into it. Then take\ (\ frac {47} {3} V_1\) volume of purified water with a gauge, slowly inject it into the container containing hydrogen peroxide, stir when injecting, so that the two are fused seamlessly, so that you can get three of hydrogen peroxide. Between operations, be careful not to splash the solution, and pay attention to protection to ensure safety.
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