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  • Lewis Structure of Hydrogen Bromide

Lewis Structure of Hydrogen Bromide

Lewis Structure of Hydrogen Bromide:

Hydrogen atoms ($H $) have 1 dollar $electrons in the outermost layer and bromine atoms ($Br $) have 7 dollars $electrons in the outermost layer. When forming hydrobromic acid molecules, hydrogen atoms and bromine atoms form covalent bonds by sharing a pair of electrons.

Its Lewis structure can be expressed as: $H:\ ddot {Br}: $, where the pair of electrons between hydrogen and bromine is represented by "$: $", and the six points around the bromine atom represent its lone pair of electrons that do not participate in bonding.

In the writing process, first determine the atomic symbols of hydrogen and bromine. Hydrogen has only one valence electron and tends to share electrons with other atoms to achieve a stable structure. As a halogen element, bromine has 7 dollars electrons in the outermost layer. After sharing one electron with hydrogen, an 8 dollars electron stable structure is formed around the bromine atom, and the hydrogen atom reaches a 2 dollars electron stable structure. This constitutes the Lewis structure of the hydrobromic acid molecule.