Shanxian Chemical
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PotassiumIodideAndHydrogenPeroxideReactionEquation
Description of the reaction of potassium iodide and hydrogen peroxide
The reaction of potassium iodide ($KI $) and hydrogen peroxide ($H_ {2} O_ {2} $) is quite fascinating in the field of chemistry. When the two meet, a wonderful change occurs.
Looking at the reaction, hydrogen peroxide has the property of oxidation, and iodine ions in potassium iodide have the ability to reduce. When the two contact, the valence state of oxygen in hydrogen peroxide changes, and iodine ions are oxidized. The chemical reaction equation is as follows: $2KI + H_ {2} O_ {2} + H_ {2} SO_ {4} = I_ {2} + K_ {2} SO_ {4} + 2H_ {2} O $ (in an acidic environment, this is a common reaction path). In this reaction, hydrogen peroxide acts as an oxidant to oxidize iodine ions to iodine elemental matter. The appearance of iodine elemental matter can be observed by the change of color of the solution. The colorless liquid gradually turns brown, which is the characterization of iodine elemental matter in solution.
Furthermore, in the reaction, the oxygen atoms decomposed by hydrogen peroxide are very active, interacting with iodine ions, causing iodine ions to lose electrons, and themselves to gain electrons and change valence. This process, the wonderful transfer of electrons, makes chemical changes wonderful. And potassium iodide in the reaction, like a fuze, triggers the decomposition of hydrogen peroxide and the chain of oxidation, resulting in this unique chemical landscape, allowing us to glimpse the mystery of chemical changes and the wonder of the transformation of sensitive substances.
The reaction of potassium iodide ($KI $) and hydrogen peroxide ($H_ {2} O_ {2} $) is quite fascinating in the field of chemistry. When the two meet, a wonderful change occurs.
Looking at the reaction, hydrogen peroxide has the property of oxidation, and iodine ions in potassium iodide have the ability to reduce. When the two contact, the valence state of oxygen in hydrogen peroxide changes, and iodine ions are oxidized. The chemical reaction equation is as follows: $2KI + H_ {2} O_ {2} + H_ {2} SO_ {4} = I_ {2} + K_ {2} SO_ {4} + 2H_ {2} O $ (in an acidic environment, this is a common reaction path). In this reaction, hydrogen peroxide acts as an oxidant to oxidize iodine ions to iodine elemental matter. The appearance of iodine elemental matter can be observed by the change of color of the solution. The colorless liquid gradually turns brown, which is the characterization of iodine elemental matter in solution.
Furthermore, in the reaction, the oxygen atoms decomposed by hydrogen peroxide are very active, interacting with iodine ions, causing iodine ions to lose electrons, and themselves to gain electrons and change valence. This process, the wonderful transfer of electrons, makes chemical changes wonderful. And potassium iodide in the reaction, like a fuze, triggers the decomposition of hydrogen peroxide and the chain of oxidation, resulting in this unique chemical landscape, allowing us to glimpse the mystery of chemical changes and the wonder of the transformation of sensitive substances.
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