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Sodium Hydrogen Carbonate Molar Mass
The theory of the molar mass of baking soda
often lies in the subtleties. Now the molar mass of baking soda (sodium bicarbonate, $NaHCO_ {3} $) is the basis of chemistry.
To know the molar mass of $NaHCO_ {3} $, when the relative atomic mass of each element is known. For sodium ($Na $), the relative atomic mass is about 23 dollars $; for hydrogen ($H $), it is about 1 dollar $; for carbon ($C $), it is about 12 dollars $; for oxygen ($O $), it is about 16 dollars $.
$NaHCO_ {3} $contains sodium atom one, hydrogen atom one, carbon atom one, and oxygen atom three. According to the arithmetic of molar mass, its value is equal to the sum of the relative atomic masses of each atom multiplied by the number of atoms.
Then the molar mass of $NaHCO_ {3} $is: 23 dollars\ times1 + 1\ times1 + 12\ times1 + 16\ times3 $
$= 23 + 1 + 12 + 48 $
$= 84 $ ($g/mol $).
The molar mass of $NaHCO_ {3} $is also. Knowing this value is of great use in chemical experiments, calculations, and analysis of reactions. The amount of deductible substances and the proportion of measurable reactions are really key data for chemical inquiry. Therefore, scholars should understand the reason and be familiar with the calculation to explore the mystery of chemistry.
often lies in the subtleties. Now the molar mass of baking soda (sodium bicarbonate, $NaHCO_ {3} $) is the basis of chemistry.
To know the molar mass of $NaHCO_ {3} $, when the relative atomic mass of each element is known. For sodium ($Na $), the relative atomic mass is about 23 dollars $; for hydrogen ($H $), it is about 1 dollar $; for carbon ($C $), it is about 12 dollars $; for oxygen ($O $), it is about 16 dollars $.
$NaHCO_ {3} $contains sodium atom one, hydrogen atom one, carbon atom one, and oxygen atom three. According to the arithmetic of molar mass, its value is equal to the sum of the relative atomic masses of each atom multiplied by the number of atoms.
Then the molar mass of $NaHCO_ {3} $is: 23 dollars\ times1 + 1\ times1 + 12\ times1 + 16\ times3 $
$= 23 + 1 + 12 + 48 $
$= 84 $ ($g/mol $).
The molar mass of $NaHCO_ {3} $is also. Knowing this value is of great use in chemical experiments, calculations, and analysis of reactions. The amount of deductible substances and the proportion of measurable reactions are really key data for chemical inquiry. Therefore, scholars should understand the reason and be familiar with the calculation to explore the mystery of chemistry.
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